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3x^2-58x-50=0
a = 3; b = -58; c = -50;
Δ = b2-4ac
Δ = -582-4·3·(-50)
Δ = 3964
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{3964}=\sqrt{4*991}=\sqrt{4}*\sqrt{991}=2\sqrt{991}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-58)-2\sqrt{991}}{2*3}=\frac{58-2\sqrt{991}}{6} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-58)+2\sqrt{991}}{2*3}=\frac{58+2\sqrt{991}}{6} $
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